Algorithms
Data Structures & Algorithms evaluate a candidate's problem-solving skills, coding proficiency, and understanding of computer science fundamentals. These questions often cover data structures, algorithms, system design, and programming concepts.
Detect If Two Integers Have Opposite Signs
In this question, input two numbers and detect if they have opposite signs. We solve using bitwise XOR operator
Find Odd Occurring Element
In this coding question, we find the odd-appearing element using bitwise xor. This algorithm is simple yet powerful.
Swap Two Numbers
In this coding question, we input two numbers and swap them without using the swapping logic.
Solution Review: Power of 2
Let's solve this using brain kernighan's algorithm. This is optimized to O(1) time and space.
Solution Review: Check If a Given Number is Even/Odd
This is a solution to another Bitwise question. Think of the rightmost bit of a number and think of some logic that could solve this. We solve using AND operator with O(1) time Complexity.
Solution Review: Count Set Bits Or Number of 1 bit's
We saw an algorithm to solve this problem in the previous lesson. Let’s see how to solve this more efficiently using Briann’s Algorithm. This is a faster execution than the previous naive approach.
How to reverse the letters in a string in Java
In this article, we'll learn various ways to reverse strings in Java. An algorithmic approach with a flow chart and steps. Using java API methods to solve this problem and rotate kth elements or characters in an array.
Number Of Flips Required To Make a|b Equal to c
We need to write a program with minimum flips to make the two bits’ OR operation equal a number. If you understand the OR operations clearly, this problem will be a good challenge for your skills.
Challenge 3: Power of 2
We solve by making use of the & operator in computers. There are many ways to solve this, of which two approaches are simple, and one is a more complex but better solution.
Switch Sign of a Number
We make use of bit manipulation to solve this problem. using a NOT operator.